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stripos

(PHP 5)

stripos --  Find position of first occurrence of a case-insensitive string

Description

int stripos ( string haystack, string needle [, int offset] )

Returns the numeric position of the first occurrence of needle in the haystack string. Unlike strpos(), stripos() is case-insensitive.

Note that the needle may be a string of one or more characters.

If needle is not found, stripos() will return boolean FALSE.

警告

本函数可能返回布尔值 FALSE，但也可能返回一个与 FALSE 等值的非布尔值，例如 0 或者 ""。请参阅布尔类型章节以获取更多信息。应使用 === 运算符来测试本函数的返回值。

例 1. stripos() examples

<?php
$findme    = 'a';
$mystring1 = 'xyz';
$mystring2 = 'ABC';

$pos1 = stripos($mystring1, $findme);
$pos2 = stripos($mystring2, $findme);

// Nope, 'a' is certainly not in 'xyz'
if ($pos1 === false) {
    echo "The string '$findme' was not found in the string '$mystring1'";
}

// Note our use of ===.  Simply == would not work as expected
// because the position of 'a' is the 0th (first) character.
if ($pos2 !== false) {
    echo "We found '$findme' in '$mystring2' at position $pos2";
}
?>

If needle is not a string, it is converted to an integer and applied as the ordinal value of a character.

The optional offset parameter allows you to specify which character in haystack to start searching. The position returned is still relative to the beginning of haystack.

注意: 本函数可安全用于二进制对象。

See also strpos(), strrpos(), strrchr(), substr(), stristr(), strstr(), strripos() and str_ireplace().

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